The sum of two numbers is 72 and their difference is 26. find two numbers?

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  23, 49

Step-by-step explanation:

Let s represent the smaller of the two numbers. Then the larger is s+26, and the sum is ...

  s + (s+26) = 72

  2s = 72 -26

  s = (72 -26)/2 = 23

Then the larger number is

  s +26 = 49

The two numbers are 23 and 49.

The reason we wrote the solution this way is to show you that the smaller number is half the difference between the given sum (72) and difference (26). This is the generic solution to a "sum and difference" problem. The smaller number is always half the difference of the give sum and difference. (Similarly, the larger is always half the sum of the given sum and difference.)

That is, the two numbers are always half the sum ± half the difference:

  72/2 ± 26/2 = {36+13, 36-13} = {49, 23}

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)