Factor 64b-16c64b−16c64, b, minus, 16, c to identify the equivalent expressions. Choose 2 answers: Choose 2 answers: (Choice A) A 16(4b-c)16(4b−c)16, left parenthesis, 4, b, minus, c, right parenthesis (Choice B) B 4(16b-4)4(16b−4)4, left parenthesis, 16, b, minus, 4, right parenthesis (Choice C) C 8(8b+2c)8(8b+2c)8, left parenthesis, 8, b, plus, 2, c, right parenthesis (Choice D) D 2(32b-8c)2(32b−8c)

the answer is su.k.my? ? co.kc

first one because it can't have a fraction in it

step-by-step explanation:

no

step-by-step explanation:

answer

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.