Given p(x) = 2x^2 + 5x – 8 and q(x) = 7x + 4, what is (p + q)(x)? (x^2 means x squared) A (p + q)(x) = 2x^2 + 12x – 4 B (p + q)(x) = 2x^2 – 2x – 12 C (p + q)(x) = –5x^2 + x – 8 D (p + q)(x) = 9x^2 + 9x – 8

4y - 6 + y^2 - 9 = y^2 + 4y - 15

y^2 term

terms

- terms

total of 3 terms when simplified

step-by-step explanation:

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen

answer is  

d.

all of the above

hope you get this right

25/32 is the simplest form