The entry tickets at a community fair cost $5 for children and $10 for adults. On a certain day 1000 people entered in the fair and $7,100 is collected. How many adults and how many children were at the fair?

C = 580 children.

A = 420 adult.

Step-by-step explanation:

Let the number of children be C.

Let the number of adult be A.

Translating the word problem into an algebraic equation, we have;

A + C = 1000  equation 1

10A + 5C = 7100  equation 2

A = 1000 - C equation 3

Substituting eqn 3 into eqn 2, we have;

10(1000 - C) + 5C = 7100

10000 - 10C + 5C = 7100

10000 - 7100 = 10C - 5C

2900 = 5C

C = 2900/5

C = 580 children.

Now, to find the value of A.

From equation 3;

A = 1000 - C

A = 1000 - 580

A = 420 adult.

fourth month

step-by-step explanation:

it is the one with the most keychains.

the perimeter is increased by a factor of 2