Four tenths of the print area of the newspaper carried news. The rest of the area was filled with advertisements. a. What percent of the print area was filled with advertisements?

b. What was the ratio of news area to advertisement area?

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

i believe the answer is the polygon, heptagon.