the path of a toy rocket is modelled by the equation y=-x^2+6x+2, where x is the horizontal distance, in metres, travelled and y is the height, in metres, of the toy rocket above the ground. what is the maximum height of the toy rocket? at what horizontal distance does the maximum height occur?

The path of a toy rocket is defined by the relation y=-3x^2+11x+4, where x is the horizontal distance, in meters, traveled and y is the height, in metres, above the ground.

Determine the zeros of the relation.

-3x^2 + 11x + 4 = 0

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3x^2 - 11x -4 = 0

Factor:

3x^2 - 12x + x - 4 = 0

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3x(x-4) + x-4 = 0

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(x-4)(3x+1) = 0

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x = 4 or x = -1/3

f(x) = -3x^2+11x+4

How far has the rocket traveled horizontally when it lands on the ground?

4 ft.

What is the maximum height of the rocket above the ground, to the nearest hundredth of a meter?

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max occurs when x = -b/2a = -11/(2*-3) = 11/6

height = f(11/6) = 14.083 ft

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

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