A soccer team gets three points for a win, one point for a tie, and zero points for a loss. The team plays ten games and has three more wins than losses. What is the greatest possible number of points the team could have?

Highest number of wins and losses can only be 6 & 3 and if u take 7 & 4 as taking 7&4 will make total 11 and we know that there was only 10 games.

So we can conclude like this

Number of wins: 6

Number of losses: 3

Number of draws: 1

Thus the points will be, (6*3)+(3*0)+(1*1)

18+0+1

=19 points

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.