A ship leaves its port and sails on a bearing of N39°50'E, at speed 22.9 mph. Another ship leaves the same port at the same time and sails on a bearing of S50°10'E, at speed 19.1
mph.
How far apart are the ships after 2 hours?

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

answer: -1

step-by-step explanation: