given a triangle with a perimeter of 56in. we know the first side is 3 inches less than twice the length of the second side, and the third side is 10 inches more than half the length of the second side. if the second side length is h, how long is the longest side? write an equation to solve for the variable

Side A = 25 in

Side B = 14 in

Side C = 17 in

Step-by-step explanation:

Perimeter of a triangle = 56 in

Side B = x

Side A = 2x - 3

Side C = 1/2x + 10

Perimeter of a triangle = side A + Side B + side C

56 = (2x -3) + x + (1/2x + 10)

56 = 2x - 3 + x + 1/2x + 10

56 + 3 - 10 = 2x + x + 1/2x

49 = 3 1/2x

Note: 3 1/2x = 3.5x

49 = 3.5x

x = 49/3.5

x = 14 in

Side B = x = 14 in

Side A = 2x - 3

= 2(14) - 3

= 28 - 3

= 25 in

Side C = 1/2x + 10

= 1/2(14) + 10

= 7 + 10

= 17 in

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

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example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.