How do I answer this?

9514 1404 393

  A.  (-∞, ∞)

  B.  (-∞, 0) U (0, ∞)

Step-by-step explanation:

A. Though the attached calculator disagrees, the value of the derivative of f(x) is actually defined at x=0. Its value is 0. There is a discontinuity in the second derivative at x=0, but both the derivative and the function are continuous there.

  differentiable on (-∞, ∞)

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B. The derivative is discontinuous at x=0, so is undefined there. The function is differentiable everywhere else.

   differentiable on (-∞, 0) U (0, ∞)

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The graphs of f(x) and its derivative are red and dotted orange, respectively.

The graphs of g(x) and its derivative are purple and dotted blue, respectively.

There are overlaps, which is why we chose to make some graphs dotted.

a .4y4

hope this !

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v