F(x) = ( - 3x² + 2 – 2)e". Find f'(x) and f''(x).
f'(2) =
f''(c)
=

-3x²-5xeˣ-eˣ

-3eˣx²-11eˣx-6eˣ

Step-by-step explanation:

I'm going to go by the picture and not what you wrote in your title.

To find the derivative of this we have to apply the product rule

(a*b)'=

a'*b+a*b'

We plug in our numbers and get

(-3x²+x-2)'*eˣ+(-3x²+x-2)*eˣ'

Now we can evaluate the derivatives and simplify

(-3x²+x-2)'= -6x+1

eˣ'=eˣ

which means we have

(-6x+1)*eˣ+(-3x²+x-2)*eˣ

Simplify

-6xeˣ+eˣ-3x²eˣ+xeˣ-2eˣ

Combine like terms

-3x²eˣ-5xeˣ-eˣ

Now we just need to find the derivative of this

We can apply the same product rule as we did before

(-3x²eˣ)'

Let's start by factoring out the -3 to get

-3(x²eˣ)'

which is equal to

-3(x²eˣ'+x²'eˣ)

Compute this and get

-3(x²eˣ+2xeˣ)= -3x²eˣ-6xeˣ

Now let's find the derivative of the second part

(-5xeˣ)'

-5(x'eˣ+xeˣ')

-5(eˣ+xeˣ)

-5eˣ-5xeˣ

Which means we have

(-3x²eˣ-6xeˣ)+(-5eˣ-5xeˣ)-eˣ

Combine like terms and get

-3eˣx²-11eˣx-6eˣ

a. 3/4 ÷ 1/8 = 6

step-by-step explanation:

in the question, the number line represents 3/4 divided into 6 equal units. each arrow represents a unit and there are a total of six arrows.

the size of each unit is 1/8 as shown.

showing that 1/8 divides 3/4 into 6 divisions:

3/4 ÷ 1/8

= 3/4 x 8/1

= 3/1 x 8/4

= 3 x 2

= 6

hence, the number line represents six divisions given by 3/4 ÷ 1/8.

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation: