Please help with explanation 1/3 of Cheryl’s savings was the same as 3/4 of Hilda’s savings. Cheryl saved $36.

(a) Find the ratio of Cheryl’s savings to Hilda’s savings.

(b) How much did Hilda save?

a) the ratio is 9:4

b) Hilda did save $16.

Step-by-step explanation:

Let's define the variables:

C = Cheryl's savings.

H = Hilda's savings.

We know that:

(1/3)*C = (3/4)*H

We also know that Cheryl saved $36, then we have:

C = $36

Now we can replace that in the above equation to get:

(1/3)*$36 = (3/4)*H

$12 = (3/4)*H

$12*(4/3) = H = $16

Then Hilda did save $16.

And the ratio between of Cheryl's savings to Hilda's savings is:

36 : 16

We can simplify this if we divide both by 2.

(36/2) : 16/2

18 : 8

Again, we can divide both by 2:

(18/2) : (8/2)

9 : 4

Then the ratio is 9 : 4

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation

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step-by-step explanation: