Subtract the cube root of the product of x and 3y from the square of the sum of a and b.

a^2 + b^2 + 2ab - (3xy)^1/3

Step-by-step explanation:

Here we want to make a subtraction

Cube root of the product of x and 3y

x * 3y = 3xy

Cube root of this;

(3xy)^1/3

The sum of a and b is (a + b)

Square of this sum;

(a + b)^2 = a^2 + 2ab + b^2

Now, subtract the cube root

we have;

a^2 + b^2 + 2ab - (3xy)^1/3

47

step-by-step explanation:

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