-Geometry 1 FIND THE QUADRANTS OF POINT P of triangle PST, a 45°-45°-90° triangle with vertices S(3, −5) and T(−4, 2) and mangleS = 90°. P is in Quadrant I.

Answer in simplest radical form.

Please help it would be very much appreciated (:

Coordinates of P:  (10,2)

Step-by-step explanation:

Slope of ST = (2-(-5))/(-4-3) = -1

angle S = 90° so Slope of SP = 1

P(10,2)

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

i can answer this if i have the answer choices