Find the smaller of 2 consecutive integers, x, if the sum of the smaller and 4 times the larger is 44.

8

Step-by-step explanation:

Find the smaller of 2 consecutive integers, x, if the sum of the smaller and 4 times the larger is 44.

Two consecutive integers are represented as:

Smaller integer = x ,

Larger Integer = x + 1

If the sum of the smaller and 4 times the larger is 44

x + 4(x + 1) = 44

x + 4x + 4 = 44

5x + 4 = 44

5x = 44 - 4

5x = 40

x = 40/5

x = 8

Therefore, the smaller of 2 consecutive integers which is x = 8