Determine the equation of a line that passes through the point (3,-2) and is PERPENDICULAR to the equation y= 3x - 1

Y= -1/3x + 5

If the line is perpendicular, it means the slope is negative reciprocal of 3, which is -1/3.

Equation where b (y-intercept) is unknown:
y= -1/3x + b

Replace x with 3 and y with -2 since the line passes through those points.

-2= -1/3(3) + b
-2= -3 + b

Add 3 to both sides of the equation:
1=b, the y-intercept is 1.

The full equation:
y = -1/3x + 1

It should be a or d i’m not sure