Solve the equation for b 4a + 6c – 2b = 12 .

b=2a+3c−6

Step-by-step explanation:

Let's solve for b.

4a+6c−2b=12

Step 1: Add -4a to both sides.

4a−2b+6c+−4a=12+−4a

−2b+6c=−4a+12

Step 2: Add -6c to both sides.

−2b+6c+−6c=−4a+12+−6c

−2b=−4a−6c+12

Step 3: Divide both sides by -2.

−2b

−2

=

−4a−6c+12

−2

b=2a+3c−6

b=2a+3c−6

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a