What is the value of "twelve more than the quotient of a number and two, decreased by four" when n = 4?

10

Step-by-step explanation:

Let

the number = n

The quotient of a number and two = n / 2

twelve more than the quotient of a number and two,

(n/2 + 12)

twelve more than the quotient of a number and two, decreased by four

(n/2 + 12) - 4

when n = 4?

(n/2 + 12) - 4

= (4/2 + 12) - 4

= (2 + 12) - 4

= 14 - 4

= 10

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

47

step-by-step explanation: