Write the equation of a line that is parallel to the line y=4x+2 and passes through the point (4,1)

y = 4x-13

Step-by-step explanation:

The standard equation of the line is y = mx+c

m is the slope

c is the intercept

Given the equation y = 4x+2

The slope m = 4

Substitute m = 4  and the given point into the formula y = mx+c

1 = 4(4)+c

1 = 14+c

c = -13

Get the equation

Recall that y = mx+c

y = 4x + (-13)

y = 4x-13

Hence the required equation is y = 4x-13

hello i might . what do you need.

friend me

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0