for a moving object, the force acting on the object varies directly with the object acceleration. When a force 42N act on a certain object, the acceleration of the object is 6m/s square. If the force is changed to 28 N, what will be the acceleration of the object?

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

is there a question here?

step-by-step explanation:

0.038

step-by-step explanation:

where does the z at is it on the x axes or on the y axes any way if it is on the y axes put it horizontally and if it is on the x axes put it vertically