The Acculturation Rating Scale for Mexican Americans (ARSMA) is a psychological test that measures the degree to which Mexican Americans are adapted to Mexican/Spanish versus Anglo/English culture. The range of possible scores is 1.0 to 5.0, with higher scores showing more Anglo/English acculturation. The distribution of ARSMA scores in a population used to develop the test is approximately Normal with mean 3.0 and standard deviation 0.8. A researcher believes that Mexicans will have an average score near 1.7 and that first-generation Mexican Americans will average about 2.1 on the ARSMA scale. What proportion of the population used to develop the test has scores below 1.7? Between 1.7 and 2.1?

The proportion of the population used to develop the test that has scores below 1.7 is 0.063.

The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The distribution of ARSMA scores in a population used to develop the test is approximately Normal with mean 3.0 and standard deviation 0.8.

This means that

What proportion of the population used to develop the test has scores below 1.7?

This is the pvalue of Z when X = 1.7. So

has a pvalue of 0.063

The proportion of the population used to develop the test that has scores below 1.7 is 0.063.

Between 1.7 and 2.1?

This is the pvalue of Z when X = 2.1 subtracted by the pvalue of Z when X = 1.7.

X = 2.1

has a pvalue of 0.1292

X = 1.7

has a pvalue of 0.063

0.1292 - 0.063 = 0.0662

The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.

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if you could provide answer choices that might allow me to answer the question easier if my above answer isn't an option! (: