![{ \sqrt[3]{8} }^{ \frac{1}{4}x } = {2}^{ \frac{1}{4} x} = {8}^{ \frac{1}{3} \times \frac{1}{4}x } \\ = {8}^{ \frac{1}{12} x} \\ = { \sqrt[12]{8} }^{x}](/tpl/images/1102/4579/a8539.png)
Which is equivalent to the square root
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