how many footballs fields (with dimensions 300 ft by 160 ft) are needed to accommodate 50,000 students if each student has 4 square feet to stand?

The area of the polo field is 300 yd x 160 yd = 48000 yards

The football field is 160 feet wide. THere are 3 feet per yard, so

the football field is 160/3 = 53 and 1/3 yards wide.

So the area of the football field is 100 yards x 53 1/3 yards

                                            = 100 yards x 160/3 yd

                                            = 16000/3 square yards

                                            =  5333 and 1/3 square yards

Dividing these areas, then they will need 48000 / (5333 and 1/3)

                                                          48000 / (16000/3) =

                                                          48000 * 3 / 16000  <-- dividing fractions; KFC: keep, flip, change; (reciprocal)

                                                           3 * 3     < 48000 cancels 16000 3 times

                                                             9

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)