There is an urn containing 10 marbles numbered 1 to 10. We sample 4 marbles without replacement. What is the probability that our sample contains the marbles labeled 1 and 2

Step-by-step explanation:

The easiest way to do this is to assume you don't get a 1 or 2. You make your first draw from 8.

8 * 7 * 6 * 5 = 1680

The total number of ways of drawing 4 marbles is

10*9 * 8 * 7 = 5040

P(`(1 or 2) ) = 1680 / 5040 = 0.33333

The probability of getting a 1 or 2 in 4 throws = 1 - 0.3333 = 0.66667

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2