Basic Triangle Proofs (Congruence Only - No CPCTC) Given:

AB⊥ BC

AD⊥ DC

BC≅ AD

Prove: △ABC≅△CDA.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

could you provide figure.

i don’t see a picture

hi there, i would be interested to you with your test, may you add the questions and answer options.

- : )