The total perimeter of the fence is 68 ft and the area is 240 square feet. Based on this information, what are the dimensions of the fence?

6ft by 40ft

Step-by-step explanation:

Perimeter = 2(L+W)

Area = LW

L is the length of the fence

W is the width

Given

P = 68ft

A = 240ft²

Substitute into the formula

68 = 2L+2W ... 1

240 = LW... 2

From 1;

34 = L+W

L = 34-W ... 3

Substitute 3 into 2

From 2;

LW = 240

(34-W)W = 240

34W - W² = 240

- W²+34W = 240

W²-34W - 240 = 0

W²+6W-40W - 240 = 0

W(W+6)-40(W+6) = 0

W-40 = 0

W = 40feet

Since

34 = L+W

34 = L + 34

L = 6ft

Hence the dimension of the fence is 6ft by 40ft

a=r

d=q

c=p

b=s

hope this !

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.