Suppose someone gives you 6 to 1 odds that you cannot roll two even numbers with the roll of two fair dice. This means you win 6 dollars if you succeed and lose 1 dollar if you fail. What is the expected value of this game to you. What can you expect if you play 200 times

0.75 ;

150

Step-by-step explanation:

Probability of rolling two even numbers :

{1, 2, 3, 4, 5, 6}

P(even) = 3 / 6 = 1/2

From a roll of 2 dice :

P(even) * P(even) = 1/2 * 1/2 = 1/4 = 0.25

P(not even) = 1 - 1/4 = 3/4

X : 6 - 1

P(x) 0.25 0.75

Expected value :

Σx*p(x) = (6*0.25) + (-1 * 0.75)

= 1.50 - 0.75

= 0.75

If 200 games are played :, n = 200

Expected value * n

0.75 * 200

= 150

1     sepan

2     encuentren

3     tenga

4     hable

5   parezca

6   llegue

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2