Recall that an American Roulette wheel has 38 possible outcomes, 18 black, 18 red and 2 green. The numbers go from 1 to 36, and the green outcomes are numbered 0 and 00. Someone places 10 bets on "1st 12", that is, that person wins if the outcome is any number between 1 and 12, included. 1. (2pts) What is the probability of losing a ’1st 12’ bet on a single spin? 2. (3pts) What is the probability of winning 7 out of the 10 total bets?

American Roulette

1. The probability of losing a  ’1st 12’ bet on a single spin is:

= 0.67

2. The probability of winning 7 out of the 10 total bets is:

= 0.23

Step-by-step explanation:

Possible outcomes in an American Roulette wheel = 38

Make-up of the outcomes = 18 black, 18 red and 2 green

Green outcomes are numbered 0 and 00

Number of wins for this person = 12

Probability of winning = 0.33  (12/36)

Number of possible losses for this person = 24

Probability of losing = 0.67 (24/36)

1. The probability of losing a  '1st 12' bet on a single spin is:

= (36 - 12)/36

= 0.67

2. The probability of winning 7 out of the 10 total bets is:

Probability of winning = 12/36 * 7/10

= 0.23

answer: options?

step-by-step explanation:

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )