A contractor claims the mean value of his compression test is 6500 psi and has astandard deviation of 500 psi. You attempt to check this by taking 8 sample measurements and findyour average is 5900 psi. If your levelof significance is 0.01, would you believe the means are the same

This value of 5675 psi by the contractor is safer than 5487.5 psi as it is of lesser value.

Step-by-step explanation:

The following parameters are given from the question above. These information is used in solving this problem.

=> The mean value of his compression test = 6500 psi, the standard deviation = 500 psi, the average of the mean = 5900 psi and the number of sample measurements = 8.

The first thing to do right now is to determine the characteristic strength, this can be calculated as below:

Characteristic strength= average of the mean - (1.65/2) × standard deviation.

Characteristic strength = 5900 - (0.825) × 500 = 5487.5 psi.

The next thing to do is to Determine the target mean strength.

Target mean strength = 5487.5 psi + 1.65 × 500 = 6312.5 psi.

The above is from taking samples from 8 samples.

Now, let's consider the characteristic strength by the contractor.

Characteristics strength = 6500 - 165 × 500 = 5675 psi.

This value of 5675 psi by the contractor is safer than 5487.5 psi as it is of lesser value.

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step-by-step explanation: