Scores turned in by an amateur golfer at the Bonita Fairways Golf Course in Bonita Springs, Florida, during and are as follows: 2018 Season: 74 78 79 77 75 73 75 77 2019 Season: 71 70 75 77 85 80 71 79 a. Use the mean (to the nearest whole number) and standard deviation (to decimals) to evaluate the golfer's performance over the two-year period. Mean Standard deviation Mean Standard deviation b. What is the primary difference in performance between and

Step-by-step explanation:

The mean for 2018 scores is:

The standard deviation for 2018 scores is:

s = 2.07

The mean and standard deviation for the year 2018 scores is:

                                     2018

Mean                                 76

Standard deviation       2.07

The mean for 2019 scores is:

The standard deviation for 2019 scores is:

s = 5.26

The mean and standard deviation for the year 2019 scores is:

                                     2019

Mean                                 76

Standard deviation       5.26

Difference: Both the two years have the same mean but the 2019 scores have higher variation as compared to 2018 scores.

Thus, the variation in scores was higher in 2019.

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step-by-step explanation:

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