Insight number 2: to evaluate the limit of a: 1. Rational function: you can factorize and cancel out what you can
2. Radicals (subtractions of square roots): multiply and divide by the
conjugate. For example:
Vx2 + 1 - x
x² + 1 - x²
V x2 + 1 - x=
x2 + 1 + x) =
Vx2 + 1 + x
Vx2 + 1 + x
1
Vx2 + 1 + x
3. Trigonometric functions: try to connect your limit with important
sin (x)
trigonometric limits like limx-10 = 1
If you are stuck with a trig limit, express all the trig functions in terms
of sine and cosine.
4. If you are composing continuous functions, you can pass the limit
inside the external function: limz-a f(g(x)) = f(limz-a g(x))

step-by-step explanation:

he will have 300 because he is really broke and 300 is in his imangine

step-by-step explanation: he ehe heh step by the thy

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.