Y= sin 20
Y= 3 cos2t
Y= 4 sin(3t-2)
Y= 4 cos(θ+2)
Mathematics, 09.02.2021 14:30 jennemylesp19oy5
Y= 2 sin θ
Y= 3 cos θ
Y= sin 20
Y= 3 cos2t
Y= 4 sin(3t-2)
Y= 4 cos(θ+2)
Y= 4 sin(3t-2)+3cos2t
Y= 2cos 3x-3 sin (2x+1)
Y= 6cos 3x/4 +2sin x/2
Y= 9sin (2θ/3-1) -14cos (30/2+1)
Answers: 3
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You know the right answer?
Y= 2 sin θ
Y= 3 cos θ
Y= sin 20
Y= 3 cos2t
Y= 4 sin(3t-2)
Y= 4 cos(θ+2)
Y= sin 20
Y= 3 cos2t
Y= 4 sin(3t-2)
Y= 4 cos(θ+2)
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