IF ANYONE CAN ANSWER THIS CORRECTLY I WILL GIVE THEM BRAINLIEST. 8 - i

3-2i

If the expression above is rewritten in the form a+bi, where a and b are real numbers, what is the value of a? (Note: i=√−1)

Re(8−i3−2i)=Re(2+i)= 2

Step-by-step explanation:

So you are asking for  Re(8−i3−2i)

First problem is, we haven’t got something which looks like a+bi here, so we have to simplify (8-i)/(3–2i).

Multiply numerator and denominator by the conjugate of the latter:

8−i3−2i=(8−i)(3+2i)13

Simplify:

=26+13i13=2+i

So  Re(8−i3−2i)=Re(2+i)= 2

So you are asking for  Re(8−i3−2i)

First problem is, we haven’t got something which looks like a+bi here, so we have to simplify (8-i)/(3–2i).

Multiply numerator and denominator by the conjugate of the latter:

8−i3−2i=(8−i)(3+2i)13

Simplify:

=26+13i13=2+i

So  Re(8−i3−2i)=Re(2+i)= 2

Step-by-step explanation:

ci

step-by-step explanation: