The graph shown represents the function h(x) = p(x) * q(x) * r(x). Which functions could be p(x), q(x), and r(x)

A. p(x) = x + 2; q(x) = -x + 1; r(x) = -5x - 1
B. p(x) = 4x - 2;q(x) = -3x + 1; r(x) = -x - 2
C. p(x) = x - 2; q(x) = x + 1; r(x) = 5x + 1
D. p(x) = 4x + 2; q(x) = 3x - 1; r(x) = x + 2​

the balance is found at the link

step-by-step explanation:

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

believe it or not anna is correct good job anna give me a fist bump there u go gal