What is the x-coordinate of the point where the lines x=4y−8 and 12x+y=11 intersect?

I like to work with the slope-intercept form of the line:

x=4y-8 �> y = (1/4)x + 2 (1)

12x+y=11 �> y = -12x + 11 (2)

At the point where they intersect the two y values must be equal, so set eq(1) = eq(2):

(1/4)x + 2 = -12x + 11

( (1/4) + (48/4))x = 9

(49/4)x = 9

Ans: x = 36/49

Check: Plug in x=36/49 to eq(1) and eq(2) to make sure they produce identical y values:

(1) y = (1/4)(36/49) + 2 = (9/49) + (98/49) = 107/49

(2) y = -12(36/49) + 11 = (-432/49) + (539/49) = 107/49 (they match)

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

answer: it's d

step-by-step explanation: