Find the 18h term of the arithmetic sequence whose common difference is d=4 and whose first term is a, =3.

the 18th term is 71

Step-by-step explanation:

The general form for any term "n" in an arithmetic sequence is:

a(n) = a1 + (n-1) * d

where "d" is the common difference.

So, in our case we have:

a(n) = 3 + (n-1) *4

Therefore, the 18th term will be:

a(18) = 3 + (18 - 1) 4 = 3 + 17 * 4 = 71

x= 149. 24+7=31. 180-31=149

your welcome