suppose the distnace in feet that an object travels t seconds is given by the formula d=64t^2 how far would the object travel after 1.5 * 10^3 seconds

The object travels 144,000,000 feet.

Step-by-step explanation:

The distance the object travel after t seconds is given by:

How far would the object travel after 1.5 * 10^3 seconds

This is d when , so

The object travels 144,000,000 feet.

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3