Find the tenth term of the geometric sequence with a1 = 3, and r = 2. 1377
1526
1659
1536
1500

General term of GP: a

1

r

n−1

10

th

term of GP =a

1

r

9

=45(0.2)

9

=23040×10

−9

=2.304×10

−5

-81 -56 -27 0 81

step-by-step explanation:

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft