An octagon with vertices at (-4, 2), (-2,5), (1,5), (3, 2), (3, -6), (1, -3), (-2, -3), and (4, -6) was dilated by a scale factor of 3 and with a center of dilation at the
origin. What are the coordinates of the vertices of the dilated octagon

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step-by-step explanation:

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step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)