A runner ran the last 11 m of a race in 4 s. What was the runner’s velocity in this part of the race? d=?
v=?
t=?

D= 11m

V=  2.75m/s^2

T=4s

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

(5x-1)^2= (5x)^2-2(5x)×1+(1)^2=25x^2-10x+1