Mathematics, 01.02.2020 00:51 sanfratello1081

Emeril used a total of 7 1/4 cups of flour to make three pastries. he used 2 1/4 cups of flour for the first and 2 1/3 cups for the second. how much flour did emeril use for the third pastry?

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Answer from: lburch112

2 2/3 cups of flour

Step-by-step explanation:

The question records that Emeril used a total of 7 1/4 cups of flour for three pastries.

For the first pastry, he used 2 1/4 cups of flour

For the second pastry, he used 2 1/3 cups of flour

To get how much of flour be used for the third, we add the amount he used for the first and second together and subtract that sum from the total cups of flour.

That is, 2 1/4 + 2 1/3

To add this mixed fractions, we add the whole number part first to get: 4 1/4 + 1/3

We then find the L.C.M of 4 and 3 (denominators), which is 12 and solve to get 4 7/12.

4 7/12 is the sum of the two pastries, we then subtract it from 7 1/4 i.e. 7 1/4 - 4 7/12 = 2 8/12

2 8/12 can be broken down to its simplest form which is 2 2/3.

Hence, the amount of flour used for the third pastry by Emeril is 2 2/3 cups

Answer from: Quest

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

= (2650-795)/(10-3)

= 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

m = 800/4

200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

Need 45 ! compare the rates at which each of the three students read: which student read at a fa

Answer from: Quest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is

$y\leq -x+4$

similarly, check the second related equation.

$3(1)=0$

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

$3y> x$

15 points write a system of inequalities to represent the shaded portion of the graph

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