The perimeter of a rectangle is 32 meters. The length is 5 less than twice the width. Find the length and the width of the rectangle. length:___ Width:

Let x and y be the length and width of the rectangle respectively
2(x+y)=32...(1)
x=2y-5...(2)

From (1),we have
2x+2y=32...(3)

By sub.(2) into (3),we have
2(2y-5)+2y=32
4y-10+2y=32
6y=42
y=7

By sub.y=7 into (2),we have
x=2*7-5
x=14-5
x=9

Length =9m
Width =7m