What is an equation of the line that passes through the points (2, -6) and (1, -1)? Put your answer in fully reduced form.
60 -

first find the gradient.

y2 - y1 / x2 - x1 = ((-1) - (-6)) / (1 - 2) = 5 / -1 = -5

Then find the equation of the line

y - y1 = m(x - x1)

y - (-2) = -5(x - 2)

y + 2 = -5x + 10

y = -5x + 10 - 2

y = -5x + 8

So the equation of the line is y = -5x + 8

step-by-step explanation:

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step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2