In ΔIJK, the measure of ∠K=90°, the measure of ∠J=62°, and KI = 2.7 feet. Find the length of IJ to the nearest tenth of a foot.

IJ is 3.1 feet long, approximately.

Step-by-step explanation:

In the image attached you can observe a representation of the problem.

Notice that we must find the hypothenuse of the right triangle. So, we need to use trigonometric reasons, because we have one angle and its opposite leg, that means we can use the sine reason.

\begin{gathered}sin(62\°)=\frac{2.7}{x} \\x=\frac{2.7}{0.9} \\x\approx 3.1\end{gathered}sin(62\°)=x2.7x=0.92.7x≈3.1

Therefore, IJ is 3.1 feet long, approximately