Two families that live 270 mi apart plan to meet at a park located between their two homes. both leave at 9:00 am but one family averages 12 mph faster than the other family. if the families meet at the designated spot 2 and half hours later, determine the average rate of speed for each family

Family 1 average rate of speed was 66 miles per hour, while Family 2 average rate of speed was 54 miles per hour.

Step-by-step explanation:

Since two families that live 270 mi apart plan to meet at a park located between their two homes, and both leave at 9:00 am but one family averages 12 mph faster than the other family, if the families meet at the designated spot 2 and half hours later, to determine the average rate of speed for each family, the following calculation must be performed:

Family 1: ((270/2) + (12 x 2.5)) / 2.5

Family 1: (135 + 30) / 2.5

Family 1: 165 / 2.5

Family 1: 66 miles per hour

Family 2: (270/2) / 2.5

Family 2: 135 / 2.5

Family 2: 54 miles per hour

-1, -2, -3, -4, -6

step-by-step explanation:

55? i think maybe

step-by-step explanation: