Solve for x: (2/x-2) + (7/x^2-4) = (5/x)

a. x = -(4/3) and x = 5
b. x = (4/3) and x = 5
c. x = (4/3 and x = _5
d. x = -(4/3) and x = _5
!

The equation given in the question is

(2/x - 2) + (7/x^2 - 4) = (5/x)
(2/x-2) + (7/(x + 2)(x - 2) = (5/x)
2(x + 2) + 7/(x+ 2)(x - 2) = 5/x
(2x + 4 + 7)/(x + 2) (x - 2) = 5/x
(2x + 11)x = 5x^2 - 20
2x^2 + 11x = 5x^2 - 20
5x^2 - 2x^2 - 11x - 20 = 0
3x^2 - 11x - 20 = 0
(3x + 4) (x - 5) = 0
Either 
x = -4/3
or
x = 5
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "a".

Iwould say rat and vsu but i’m not 100% sure