Sanjay, Ajay and Anushka are employees of a company that has branches in Chennai, Bangalore and Mumbai. The company sends each of them to one of these cities at random. Let X X be a random variable that denotes the number of employees assigned to their favourite cities. If Chennai, Bangalore and Mumbai are the favourite cities of Sanjay, Ajay and Anushka, respectively, then find the possible values of X. a. X= {0,1,2}
b. X= {0,1,2,3}
c. X= {0,1,3}
d. X= {0,[infinity]}

c. X= {0,1,3}

Step-by-step explanation:

We have these possible outcomes:

None assigned to their favorite cities.

One assigned to their favorite city(The other two are assigned to the other's favorite city).

All are assigned to their favorite city.

Why is two not possible?

If two peooke are assigned to their favorite city, the third person necessary has to be assigned to their favorite city, as it will be the only option remaining.

So the correct answer is given by option c.

the answer is simply just 6n add the two together as they have an n

one set of data has more variation than the other. hope this !