Find the minimum y-value on the graph y=f(x)
f(x)= x^2+4x-5

There are two ways to solve the problem: using calculus and algebra. For this, I'll be using the algebraic way. The function is parabolic, thus the minimum value is the ordinate of the vertex. Using completing the square, we could get the vertex of the parabola.

y = x^2 + 4x - 5y = x^2 + 4x + 4 - 5 - 4y = (x + 2)^2 - 9Vertex is (-2, -9). 

Therefore, the minimum value is -9.

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You need to divide 210 square inches by 35 inches and that’s going to give you 6 inches and that’s the length of the hypothenuse of the right triangle i hope that this you : )

We’re gonna need a picture to refer to in order to figure it out. try reposting your question with the picture included.