Write the equation of the line in fully simplified slope-intercept form.

y=4/5x+8

Step-by-step explanation:

in order to find the slope intercept form of a line the first step you have to take is finding where the line meets the y-axis

in this case it would be at (0,8)

so therefore 8 would be your y-intercept (which we label as B)

then in order to find the slope, what i do is find the next point in the middle of the graph (-5,4)

and then i find the distance between the y-intercept and the next point

and in order to do this i first take 8 and subtract by 4 in order to get to (0,4)

and then it moves to the left so i also subtract -5 because the next point is located on (-5,4)

so when doing this it creates our equation of y=mx+b

and that turns into y=4/5x+8

desmos is also a website that can help you with graphing and visualizing things out as well and can also be useful for trial and error when it comes to slopes and graphs and what not.

anyways hope this helps!

if it did please make sure to rate it, leave a like, and give me the brainliest!

have a great day!

your answer would be 10x - 1

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}