Fireworks are set off from a hill 80 feet above the Mississippi. The outer shells will fall after exploding at its maximum height. The firework's height
about the surface of the river is given by the function h(t) = -16t^2 + 64t +
80. What is the height of the rocket after 1.5 seconds?

752 ft

Step-by-step explanation:

Assuming t represents time, and the time we are trying to find is how high the rockets go after 1.5 seconds, we must take the equation and put 1.5 in wherever t occurs, this looks like:

-16(1.5)²+64(1.5)+80

solving this, we get:

-24²+96+80

576+96+80

752

i believe that the answer is

b. y-1=-2(x-4)

hope this !

could u provide us some answer choices or hmm idk maybe a table for us to anser with ? ?